Force Required To Bend Sheet Metal Folding

The slack between the wipe die and the punch plays an important role in getting a good result.

Force required to bend sheet metal folding.

Wipe bending or edge bending is another way to bend sheet metal edges. The total strength of bending of a sheet is directly proportional to the length of bending. The strength of the table is the force required to bend sheet metal up to 1 m in length. As a result the wipe die also determines the bend s inner radius.

F 2 ybh2 4 fl 4 m max f bh2y l l σ ε e. The bend allowance formula takes into account the geometries of bending and the properties of your metal to determine the bend allowance. It is important to make sure that the sheet is properly pushed onto the wipe die. When the sheet metal is put through the process of bending the metal around the bend is deformed and stretched.

This tool allows you to determine tonnage internal radius v die opening and minimum flange you just have to insert the characteristics of the sheet metal to be bent. A punch exerts force at the correct spot bending the sheet metal between. You should choose at least 100ton press brake. The bending force can be calculated from the sheet thickness die opening bend length and the ultimate tensile strength of the material.

The tool can calculate the required bending force for bending aluminum stainless steel mild steel and weldox or strenx high strength steels. As this happens you gain a small amount of total length in your part. Now we know that for bending the sheet metal with 4mm thickness and 1m length the required tonnage is 330kn. The material thickness will be measured in decimal form not by the gauge number.

ε y σy bending force requirement punch workpiece t die w force t sheet thickness w width of die opening l total length of bend into the page uts ultimate tensile. Discover all our calculation tools in the calculators section of the top menu. Forces needed to bend sheet metal. You will need to know your material thickness mt the bend angle b the inside radius ir and the k factor k.

If bend the 4mm sheet in 3 meters then the tonnage should be 330 3 990kn which equals to 101 ton. Understanding the bend allowance and consequently the bend deduction of a part is a crucial first step to understanding how sheet metal parts are fabricated. The die ratio may be entered to calculate the die opening which is typically 6 to 18 times the sheet thickness. Here we come to the conclusion.

Stress distribution through the thickness of the part s s y y y y y.